Nikon P7100 has a
10.0MP 1/1.7-inch (7.44 x 5.58 mm ) sized CCD sensor and features Expeed C2 processor. On the other hand, Konica Minolta 5D has a
6.0MP APS-C (23.5 x 15.7 mm ) sized CCD sensor .
Below you can see the P7100 and 5D sensor size comparison.
Sensor Size and Resolution Comparison image of Nikon P7100 and Konica Minolta 5D Cameras
As seen above, Konica Minolta 5D has a 8.9x Larger sensor area than Nikon P7100. Larger sensors give photographer more control on the depth of field and blurry background compared to smaller sensor when shot in same focal length and aperture.
DxOMark Sensor Scores
DxOMark is a benchmark that scientifically assesses image quality of camera sensors. It scores camera sensors for color depth (DXO Portrait), dynamic range (DXO Landscape) and low-light sensitivity (DXO Sports), and also gives them an overall score. Nikon P7100 and Konica Minolta 5D sensors have been tested by DxO and the results show that 5D has a better overall score of 58, 17 points higher compared to P7100's score of 41.
Model
Overall
Color Depth
Dynamic Range
Low-light ISO
Nikon P7100
41
19.4 bits
10.7 Evs
165 ISO
Konica Minolta 5D
58
21.3 bits
11.1 Evs
605 ISO
Sensor size sets the circle of confusion, so it drives how much depth of field each
of these bodies gives you at a given aperture. You can calculate it exactly for the
Nikon P7100
or the
Konica Minolta 5D ,
including hyperfocal distance.
One thing to watch when comparing these two: they have different sensor sizes
(1/1.7-inch versus APS-C),
so compare them at the same framing rather than the same focal length.
Put the same focal length on the smaller sensor and it will show less depth of
field, not more, because it also crops tighter. The calculator shows the
full frame equivalent focal length for each body so you can match the framing.
